JavaScript: why does [1, 2, 10].sort() put 10 before 2?

Question

[1, 2, 10].sort()  // [1, 10, 2]
Is this a bug?

Lin Mei · Accepted Answer

No — Array.prototype.sort compares elements as strings by default, and "10" < "2". Pass a comparator:
[1, 2, 10].sort((a, b) => a - b)  // [1, 2, 10]
Since ES2023 there is also toSorted, which does not mutate the original array.

Dmitri Vasko · Answer

Classic. localeCompare is the comparator to use for human-readable strings.

JavaScript: why does [1, 2, 10].sort() put 10 before 2?

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